The alternate view is to think about how nature itself might be trying to settle on a voltage at the center connection of the two resistors. This tells us the voltage ACROSS each resistor, knowing the current I and each resistor value. If R1 has 1 amp, the R2 must have 1 amp too. What that means is simply that each resistor MUST have the very same current level. "Circuit elements in series all have the same current". To get another view of the voltage divider to begin with, we know that in the most basic divider there are two resistors in series, and the first law we use is: This alternate view of a voltage divider still requires some circuit analysis concepts, but only requires understanding Ohm's law in a very simple way and the concept of equality.įirst, it's a good idea to learn algebra better because it's more widely applicable and you can solve an awful lot of problems using just algebra. I believe the question you are referring to is question 15.īack in the 1980's i was unsatisfied with 'regular' circuit analysis to some degree so i developed another way of thinking about a voltage divider. so a high resistance would pull a small current.(i am correct in thinking this arn't.(sudden sinking feeling in pit of stomach)). say an output of 10v into a load of 1 megohm would mean 10v cut up into 1 million bits and just one of those bits would be the current. and i understand the idea of an input having a high resistance. i read about the idea of a load being in parallel with the output resistor and calculating using the parallel value and the "rule of thumb" of using a load that is a minimum of ten times the output resistor. the books and sites mention that you can look at a voltage divider and figure out, "intuitively" what the answer is going to be, without using all the calculations. i have the art of electronics lab manual that i am trying to work through and a course i am trying to study (distance learning). i have read a few things about voltage dividers. because i think it is understanding electronics as well. I know how to get V/R = I but the part about understanding how to get to the above formula is what is getting me. This is the formula that it talks about, it is quoted from question 3 in the worksheet mentioned in my first post.
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